T-Score Calculator

Reviewed by CalcMulti Editorial Team·Last updated: ·Statistics Hub

The t-score calculator converts a t-statistic into a p-value for hypothesis testing, or finds the critical t-value for a given significance level and degrees of freedom. These are the two core operations needed after computing a t-statistic from raw data.

Use this tool when you already have a t-statistic (from a manual calculation or another tool) and need the corresponding p-value — or when you need to look up the critical threshold for your test. Supports one-tailed and two-tailed tests for any df from 1 to 10,000.

Formula

One-sample: t = (x̄ − μ₀) / (s / √n) df = n − 1

t
t-statistic — standardised distance from the hypothesised mean
df
degrees of freedom — n−1 for one-sample; Welch approximation for two-sample
α
significance level — typically 0.05 (5%) or 0.01 (1%)
p-value
probability under H₀ of observing |t| or greater

n−1 for one-sample

Critical t-Values — Two-Tailed Reference Table

Values shown are ±t_crit — reject H₀ if |t| exceeds this value.

dfα=0.10α=0.05α=0.025α=0.01α=0.001
16.31412.70625.45263.657636.619
32.3533.1824.1775.84112.924
52.0152.5713.1634.0326.869
101.8122.2282.6343.1694.587
201.7252.0862.4232.8453.850
301.6972.0422.3602.7503.646
601.6712.0002.2992.6603.460
1201.6581.9802.2702.6173.373
∞ (z)1.6451.9602.2412.5763.291

t-Test vs z-Test — Which Statistic to Use?

ConditionUse tUse z
Population σ known?No (estimated from sample s)Yes (known exactly)
Sample sizeAny n (essential for small n)Large n ≥ 30 with CLT
Distribution shapeNormal, or n ≥ 30 for CLTNormal or large n
Result precisionExact for normally distributed dataApproximate (CLT)
df needed?Yes — n−1 or Welch formulaNo
Converges to z when?df > 120 → virtually identicalAlways

Case Study: Evaluating a New Pain Relief Drug

A pharmacologist tested a new pain relief drug in a randomised trial. Treatment group (n=14): mean pain score reduction 8.2, SD=3.1. Control group (n=12): mean reduction 5.4, SD=3.8. She needed the p-value to support a grant report.

Welch two-sample t-statistic: t ≈ (8.2 − 5.4) / √(3.1²/14 + 3.8²/12) = 2.8 / √(0.686 + 1.203) = 2.8 / 1.374 ≈ 2.04. Welch df ≈ 21. Two-tailed p-value: p ≈ 0.054.

The result was borderline: p=0.054, just above the α=0.05 threshold. Rather than reporting "not significant," the pharmacologist reported the exact p-value alongside a 95% CI for the mean difference [−0.05, 5.65], noting the confidence interval nearly excluded zero. She recommended a larger confirmatory trial (n=40 per group), which later yielded p=0.018.

Disclaimer

This calculator is for educational purposes only and does not constitute professional advice. Results are based on standard mathematical formulas. Always verify critical calculations with a qualified professional before making important decisions.

Frequently Asked Questions