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Momentum is the quantity of motion of an object — the product of its mass and velocity: p = mv. It is a vector quantity, so direction matters. A 1000 kg car at 20 m/s has the same magnitude of momentum (20,000 kg·m/s) as a 20,000 kg truck at 1 m/s, but in very different collision scenarios their effects are quite different because of how kinetic energy scales with velocity (KE = ½mv²).
The Impulse-Momentum Theorem connects force and time to changes in momentum: J = FΔt = Δp = mv_f − mv_i. Impulse J is the product of force and the time it acts — a large force for a short time or a small force for a long time can produce the same impulse. This is why airbags increase collision time, reducing peak force and injury.
Conservation of momentum is one of physics' most powerful principles: in a closed system (no external forces), total momentum before a collision equals total momentum after: m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂. This holds for both elastic collisions (kinetic energy also conserved) and inelastic collisions (kinetic energy not fully conserved).
Worked example: A 0.1 kg ball moving at 15 m/s hits a stationary 0.4 kg ball in a perfectly inelastic collision (they stick together). By momentum conservation: 0.1×15 + 0.4×0 = (0.1+0.4)×v → v = 1.5/0.5 = 3 m/s.
p = mv | J = FΔt = Δp | m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
p = m × v
Momentum & Impulse Reference
| Formula | Description | Units |
|---|---|---|
| p = mv | Linear momentum | kg·m/s |
| J = FΔt | Impulse (= change in momentum) | N·s |
| J = Δp = mv_f − mv_i | Impulse-momentum theorem | kg·m/s |
| p_total = const | Conservation of momentum (no ext. force) | — |
| v_f = (m₁v₁+m₂v₂)/(m₁+m₂) | Perfectly inelastic collision | m/s |
| KE = ½mv² conserved | Elastic collision condition | J |
This calculator is for educational purposes only and does not constitute professional advice. Results are based on standard mathematical formulas. Always verify critical calculations with a qualified professional before making important decisions.